6.3 Reaction Stoichiometry

Learning Objectives

By the end of this section, you will be able to:

  • Explain the concept of stoichiometry as it pertains to chemical reactions
  • Use balanced chemical equations to derive stoichiometric factors relating amounts of reactants and products
  • Perform stoichiometric calculations involving mass, moles, and solution molarity

A balanced chemical equation provides a great deal of information in a very succinct format. Chemical formulas provide the identities of the reactants and products involved in the chemical change, allowing classification of the reaction. Coefficients provide the relative numbers of these chemical species, allowing a quantitative assessment of the relationships between the amounts of substances consumed and produced by the reaction. These quantitative relationships are known as the reaction’s stoichiometry, a term derived from the Greek words stoicheion (meaning “element”) and metron (meaning “measure”). In this module, the use of balanced chemical equations for various stoichiometric applications is explored.
The general approach to using stoichiometric relationships is similar in concept to the way people go about many common activities. Food preparation, for example, offers an appropriate comparison. A recipe for making eight pancakes calls for 1 cup pancake mix, 3/4 cup milk, and one egg. The “equation” representing the preparation of pancakes per this recipe is

1 cup mix + \frac{3}{4} cup milk + 1 egg → 8 pancakes

If two dozen pancakes are needed for a big family breakfast, the ingredient amounts must be increased proportionally according to the amounts given in the recipe. For example, the number of eggs required to make 24 pancakes is

24\, \textup{pancakes}\, \times \, \frac{1\, \textup{egg}}{8\, \textup{pancakes}}\, =\, 3\, \textup{eggs}

Balanced chemical equations are used in much the same fashion to determine the amount of one reactant required to react with a given amount of another reactant, or to yield a given amount of product, and so forth. The coefficients in the balanced equation are used to derive stoichiometric factors that permit computation of the desired quantity. To illustrate this idea, consider the production of ammonia by reaction of hydrogen and nitrogen:

N2(g) + 3H2(g) → 2NH3(g)

This equation shows ammonia molecules are produced from hydrogen molecules in a 2:3 ratio, and stoichiometric factors may be derived using any amount (number) unit:

\frac{2\, \textup{N}\textup{H}_{3}\, \textup{molecules}}{3\, \textup{H}_{3}\, \textup{molecules}}\,\, \textup{or}\,\,\frac{2\, \textup{doz}\, \textup{N}\textup{H}_{3}\, \textup{molecules}}{3\, \textup{doz}\, \textup{H}_{3}\, \textup{molecules}}\,\, \textup{or}\,\,\frac{2\,\textup{mol}\, \textup{N}\textup{H}_{3}\, \textup{molecules}}{3\, \textup{mol}\, \textup{H}_{2}\, \textup{molecules}}

These stoichiometric factors can be used to compute the number of ammonia molecules produced from a given number of hydrogen molecules, or the number of hydrogen molecules required to produce a given number of ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation.

Example 1: Moles of Reactant Required in a Reaction

How many moles of I2 are required to react with 0.429 mol of Al according to the following equation (see Figure 1)?

Figure 1. Aluminum and iodine react to produce aluminum iodide. The heat of the reaction vaporizes some of the solid iodine as a purple vapor. (credit: modification of work by Mark Ott)

2Al + 3I2 → 2AlI3

Solution:

Referring to the balanced chemical equation, the stoichiometric factor relating the two substances of interest is \frac{3\, \textup{mol}\, \textup{I}_{2}}{2\, \textup{mol}\, \textup{Al}}. The molar amount of iodine is derived by multiplying the provided molar amount of aluminum by this factor:

\textup{mol\, } \textup{I}_{2}\, =\, 0.429 \, \textup{mol\, Al}\, \times \, \frac{3\, \textup{mol}\, \textup{I}_{2}}{2\, \textup{mol}\, \textup{Al}}

=\, 0.644\, \textup{mol\, }\textup{I}_{2}

Check Your Learning:

How many moles of Ca(OH)2 are required to react with 1.36 mol of H3PO4 to produce Ca3(PO4)2 according to the equation 3Ca(OH)+ 2H3PO4 → Ca3(PO4)2 + 6H2O?

Answer:

2.04 mol

Example 2: Number of Product Molecules Generated by a Reaction

How many carbon dioxide molecules are produced when 0.75 mol of propane is combusted according to this equation?

C3H+ 5O2 → 3CO2 + 4H2O

Solution:

The approach here is the same as for the example above, though the absolute number of molecules is requested, not the number of moles of molecules. This will simply require use of the moles-to-numbers conversion factor, Avogadro’s number.
The balanced equation shows that carbon dioxide is produced from propane in a 3:1 ratio:

\frac{3\, \textup{mol}\, \textup{C}\textup{O}_{2}}{1\,\textup{mol}\, \textup{C}_{3} \textup{H}_{8}}

Using this stoichiometric factor, the provided molar amount of propane, and Avogadro’s number,

0.75\, \textup{mol}\, \textup{C}_{3}\textup{H}_{8}\, \times \, \frac{3\, \textup{mol}\, \textup{C}\textup{O}_{2}}{1\,\textup{mol}\, \textup{C}_{3} \textup{H}_{8}}\, \times \, \frac{6.022\, \times 10^{23}\, \textup{C}\textup{O}_{2}\, \textup{molecules}}{\textup{mol\, C}\textup{O}_{2}}\,

=\, 1.4\,\times \, 10^{24}\, \textup{C}\textup{O}_{2}\,\, \textup{molecules}

Check Your Learning:

How many NH3 molecules are produced by the reaction of 4.0 mol of Ca(OH)2 according to the following equation:

(NH4)2SO4 + Ca(OH)2  → 2NH3 + CaSO4 + 2H2O

Answer:

4.8 × 1024 NH3 molecules

These examples illustrate the ease with which the amounts of substances involved in a chemical reaction of known stoichiometry may be related. Directly measuring numbers of atoms and molecules is, however, not an easy task, and the practical application of stoichiometry requires that we use the more readily measured property of mass.

Example 3: Relating Masses of Reactants and Products

What mass of sodium hydroxide, NaOH, would be required to produce 16 g of the antacid milk of magnesia [magnesium hydroxide, Mg(OH)2] by the following reaction?

MgCl2(aq) + 2NaOH(aq) → Mg(OH)2(s) + 2NaCl(aq)

Solution:

The approach used in the two previous examples is likewise used here; that is, we must derive an appropriate stoichiometric factor from the balanced chemical equation and use it to relate the amounts of the two substances of interest. In this case, however, masses (not molar amounts) are provided and requested, so additional steps of the sort learned in the previous chapter are required. The calculations required are outlined in this flowchart:

16\, \textup{g}\, \textup{Mg}\left(\textup{OH}\right )_{2}\, \times \, \frac{1\, \textup{mol}\, \textup{Mg}\left(\textup{OH}\right )_{2}}{58.3\,\textup{g}\, \textup{Mg}\left(\textup{OH}\right )_{2}}\,\, \times \, \, \frac{2\,\textup{mol}\,\textup{NaOH}}{1\, \textup{mol\,Mg}\textup{OH}_{2}}\, \times\, \frac{40.0\, \textup{g\, NaOH}\,\, }{\, \textup{mol\ NaOH}}\,

=\, 22\textup{g\, NaOH}

Check Your Learning:

What mass of gallium oxide, Ga2O3, can be prepared from 29.0 g of gallium metal? The equation for the reaction is 4Ga + 3O2 →  2Ga2O3.

Answer:

39.0 g

Example 4: Relating Masses of Reactants

What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal components of gasoline?

2C8H18 + 2502 → 16CO2 + 18H2O

Solution:

The approach required here is the same as for the previous example, differing only in that the provided and requested masses are both for reactant species.

702\, \textup{g}\, \textup{C}_{8}\textup{H}_{18}\, \times \, \frac{1\, \textup{mol}\, \textup{C}_{8}\textup{H}_{18}}{114.23\,\textup{g}\,\, \textup{C}_{8}\textup{H}_{18}}\,\, \times \, \, \frac{25\,\textup{mol}\,\textup{O}_{2}}{2\, \textup{mol\,}\textup{C}_{8}\textup{H}_{18}}\, \times\, \frac{32.00\, \textup{g}\, \textup{O}_{2}\,\, }{\, \textup{mol}\, \textup{O}_{2}}\,

=\, 2.46\, \times \, 10^{3}\textup{g}\, \textup{O}_{2}

Check Your Learning:

What mass of CO is required to react with 25.13 g of Fe2O3 according to the equation

Fe2O3 + 3CO → 2Fe + 3CO2

Answer:

13.22 g

These examples illustrate just a few instances of reaction stoichiometry calculations. Numerous variations on the beginning and ending computational steps are possible depending upon what particular quantities are provided and sought (volumes, solution concentrations, and so forth). Regardless of the details, all these calculations share a common essential component: the use of stoichiometric factors derived from balanced chemical equations. Figure 2 provides a general outline of the various computational steps associated with many reaction stoichiometry calculations.

Figure 2. The flowchart depicts the various computational steps involved in most reaction stoichiometry calculations.

Note: AIRBAGS

Airbags (Figure 3) are a safety feature provided in most automobiles since the 1990’s. The effective operation of an airbag requires that it be rapidly inflated with an appropriate amount (volume) of gas when the vehicle is involved in a collision. This requirement is satisfied in many automotive airbag systems through use of explosive chemical reactions, one common choice being the decomposition of sodium azide, NaN3. When sensors in the vehicle detect a collision, an electrical current is passed through a carefully measured amount of NaN3 to initiate its decomposition:
2NaN3(s) → 3N2(g) + 2Na(s)
This reaction is very rapid, generating gaseous nitrogen that can deploy and fully inflate a typical airbag in a fraction of a second (~0.03–0.1 s). Among many engineering considerations, the amount of sodium azide used must be appropriate for generating enough nitrogen gas to fully inflate the air bag and ensure its proper function. For example, a small mass (~100 g) of NaN3 will generate approximately 50 L of N2.

Figure 3. Airbags deploy upon impact to minimize serious injuries to passengers. (credit: Jon Seidman)

Key Concepts and Summary

A balanced chemical equation may be used to describe a reaction’s stoichiometry (the relationships between amounts of reactants and products). Coefficients from the equation are used to derive stoichiometric factors that subsequently may be used for computations relating reactant and product masses, molar amounts, and other quantitative properties.

6.3 Reaction Stoichiometry  Exercises

  1.  Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation: 2Ga + 6HCl → 2GaCl3 + 3H2
    (a) Outline the steps necessary to determine the number of moles and mass of gallium chloride.
    (b) Perform the calculations outlined.
  2.  I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2 + 4KI → 2CuI + 4KCl + I2
    (a) How many molecules of I2 are produced?
    (b) What mass of I2 is produced?
  3.  Silver is often extracted from ores as K[Ag(CN)2] and then recovered by the reaction 2K [Ag(CN)2](aq) + Zn(s) →  2Ag(s) + Zn(CN)2(aq) + 2KCN(aq)
    (a) How many molecules of Zn(CN)2 are produced by the reaction of 35.27 g of K[Ag(CN)2]?
    (b) What mass of Zn(CN)2 is produced?
  4. What mass of silver oxide, Ag2O, is required to produce 25.0 g of silver sulfadiazine, AgC10H9N4SO2, from the reaction of silver oxide and sulfadiazine?
    2C10H10N4SO2 + Ag2O  → AgC10H9N4SO+ H2O
  5.  Carborundum is silicon carbide, SiC, a very hard material used as an abrasive on sandpaper and in other applications. It is prepared by the reaction of pure sand, SiO2, with carbon at high temperature. Carbon monoxide, CO, is the other product of this reaction. Write the balanced equation for the reaction, and calculate how much SiO2 is required to produce 3.00 kg of SiC.
  6. Automotive air bags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.
    2NaN3(s)  2Na(s) + 3N2(g) What mass of sodium azide is required to produce 2.6 ft3 (73.6 L) of nitrogen gas with a density of 1.25 g/L?
  7.  Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is the maximum mass of urea that can be manufactured from the CO2 produced by combustion of 1.00 × 103 kg of carbon followed by the reaction?
    CO2(g) + 2NH3(g)  CO(NH2)2(s) + H2O(l)
  8.  In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area and CO2 was released by the reaction. Was sufficient Na2CO3 used to neutralize all of the acid?
  9.  A compact car gets 37.5 miles per gallon on the highway. If gasoline contains 84.2% carbon by mass and has a density of 0.8205 g/mL, determine the mass of carbon dioxide produced during a 500-mile trip (3.785 liters per gallon).
  10.  What volume of a 0.750 M solution of hydrochloric acid, a solution of HCl, can be prepared from the HCl produced by the reaction of 25.0 g of NaCl with an excess of sulfuric acid? NaCl(s) + H2SO4(l)  HCl(g) + NaHSO4(s)
  11.  What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2?
    2Cu(NO3)+ 4KI ⟶ 2CuI + I+ 4KNO3
  12.  A mordant is a substance that combines with a dye to produce a stable fixed color in a dyed fabric. Calcium acetate is used as a mordant. It is prepared by the reaction of acetic acid with calcium hydroxide. 2CH3CO2H + Ca(OH)2 → Ca(CH3CO2)2 + 2H2O
  13.  What mass of Ca(OH)2 is required to react with the acetic acid in 25.0 mL of a solution having a density of 1.065 g/mL and containing 58.0% acetic acid by mass?
  14.  The toxic pigment called white lead, Pb3(OH)2(CO3)2, has been replaced in white paints by rutile, TiO2. How much rutile (g) can be prepared from 379 g of an ore that contains 88.3% ilmenite (FeTiO3) by mass?
    2FeTiO3 + 4HCl + Cl2 → 2FeCl3 + 2TiO2 + 2H2O

Glossary

stoichiometric factor

ratio of coefficients in a balanced chemical equation, used in computations relating amounts of reactants and products

stoichiometry

relationships between the amounts of reactants and products of a chemical reaction

License

Icon for the Creative Commons Attribution-NonCommercial 4.0 International License

Chemistry in Everyday Life Copyright © by Michele Lansigan is licensed under a Creative Commons Attribution-NonCommercial 4.0 International License, except where otherwise noted.

Share This Book