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Topic 3 – Layout Stairs and Stairwell Openings

Laying Out a Stringer

For detailed layout instructions, consult chapters 37 and 38 in the Carpentry textbook.

Stairwell Openings for Straight Stairs

Just as the total rise and resulting unit rise directly affects the total run and unit run, the length of a stairwell is directly determined by using the required headroom. The headroom is measured from the bottom of the upper floor directly down to the line of flight (see figure 2 below). The NBC contains headroom requirements for three different scenarios, which can be found in section 9.8.2.2:

– 2050 mm for public stairs
– 1950 for private stairs (serving a single dwelling or a house with a secondary suite)
– 1850 for stairs located under beams and ducting in secondary suites)

In order to calculate the finished opening required for a set of stairs, a minimum amount of information is required:

– Total rise
– Proposed rise and unit run formula (rise + run = 460 mm)
– Headroom required (found in the NBC)
– Upper floor construction

With the above information we can calculate all the stair components and then find the finished opening required for the set. We will complete the entire process using the following information:

  • Total Rise = 2650 mm
  • Proposed Rise = 200 mm (maximum private)
  • Use Unit Run = 460 mm – unit rise
  • Upper Floor Construction = 273 mm
  • Minimum Private Headroom

number sign U n i t s R i s e equals 2650 m m divided by 200 m m equals 13.25 equals 14 open paren r o u n d u p b e c a. u s e p r o p o s e d equals max of i m u m close paren

U n i t R i s e equals 2650 divided by 14 equals 189.29 m m equals 189 m m

U n i t R u n equals 460 m m minus 189 m m equals 271 m m

*At this point, check to see if the unit run and rise fall within code requirements. They do in this case, so we can move on.

What we can now do is look at the relationship between the two triangles we can draw, one which results from the unit rise and run, and one which results from the headroom + floor construction and the finish opening. The two resulting triangles can be directly compared as they are the same shape and ratios at different scales:

image

This can be expressed in a ratio as follows:

the fraction with numerator U n i t R i s e and denominator U n i t R u n equals H of e a. d r o o m plus the fraction with numerator F of l o o r C o n s t r u c t i o n and denominator F of i n i s h of e d O p e n i n g

It is essential to understand this relationship and how to rearrange it to suit our needs. In most cases, the opening length is the unknown dimension and we can rearrange the equation to find it:

F of i n i s h of e d S t a. i r w e l l O p e n i n g equals H of e a. d r o o m plus the fraction with numerator F of l o o r C o n s t r u c t i o n and denominator U n i t R i s e times U n i t R u n

 

*The part of the equation open paren H of e a. d r o o m plus the fraction with numerator F of l o o r C o n s t r u c t i o n and denominator U n i t R i s e close paren is also known as “uncovered treads”. The term “uncovered treads” refers to the amount of treads one would see when viewing the completed stairs from above. This value represents the ratio between the unit triangle and the headroom plus floor construction/finish opening triangle. In its essence, when we have 11.75 uncovered treads, it means the headroom + floor construction is 11.75 times bigger than the unit rise, and the finished opening is 11.75 times bigger than the unit run. See figure 4 on the next page for reference.

image

We can now plug in the known values from the example on the previous page into the formula:

F of i n i s h of e d S t a. i r w e l l O p e n i n g equals the fraction with numerator 1950 m m plus 273 m m and denominator 189 m m times 271 m m equals 2223 m m over 189 m m times 271 m m equals 11.76 times 271 m m equals 3187.4 m m

The answer for finished opening is 3187.4 mm. Often, we are looking to find the rough opening of a stairwell. In order to account for finishes such as nosing and drywall, we simply add 75 mm (3”) to the finished opening:

R o u g of h O p e n i n g equals F of i n i s h of e d O p e n i n g positive 75 m m equals 3187.4 m m plus 75 m m equals 3262.4 m m

This can also be placed directly into the finish stairwell opening:

S t a. i r w e l l R o u g of h O p e n i n g equals the fraction with numerator H of e a. d r o o m plus F of l o o r C o n s t r u c t i o n and denominator U n i t R i s e times U n i t R u n positive 75 m m open paren 3 quotation mark close paren

Split Entry Stairwells

Many homes possess a split entry stairwell, with the entrance being placed between the first and basement floors. These stairs are divided by a landing and can turn 90° or 180°. The openings for both are calculated separately. The total rise for the lower flight is the landing height (usually given), and the total rise of the upper flight is the difference between the total rise of the stairs and the landing height.

image

imageFor most cases, the upper flight will not possess enough risers to reach the desired headroom in relation to the floor above and the opening will therefore fully extend over the upper flight. When we have 10 or less risers, this can be safely assumed (this can be checked by taking the number of risers in the upper flight and multiplying it by the unit rise; if it is smaller than the headroom + floor construction, it does not go low enough to gain the required headroom). We will use the stairs in figure 6 as an example.

U n i t R i s e U p p e r F of l i g of h of t equals 570 m m division sign 3 equals 190 m m

U n i t R u n equals 460 m m minus 190 m m equals 270 m m

The components of the upper flight are first calculated in order to find the R.O. We can see that we are given the following:

  • Total Rise Upper Flight = 570 mm
  • Landing 1000 mm, Upper Floor Construction = 300 mm
  • 3 risers upper flight (pictured, proposed rise may instead be given)

From this information we will find our unit rise and unit run using rise + run = 460 mm:

U n i t R i s e U p p e r F of l i g of h of t equals 570 m m divided by 3 equals 190 m m

U n i t R u n equals 460 m m minus 190 m m equals 270 m m

We can take these values and directly calculate the R.O. using the following formula:

R period O period U p p e r F of l i g of h of t equals open paren number sign t r e a. d s x u n i t r u n close paren plus l a. n d i n g l e n g of t h plus 75 m m open paren f of o r f of i n i s h of e s close paren

R period O period U p p e r F of l i g of h of t equals open paren 2 times 270 m m close paren positive 1000 m m plus 75 m m equals 1615 m m

We can now calculate the R.O. for the lower flight of stairs. First the unit rise and run will be calculated. The total rise of the lower flight is fixed at the landing height. In order to get a value as close as possible to the upper flight, we will use the upper flight unit rise as our proposed rise:

number sign R i s e s L o w e r F of l i g of h of t equals 2100 m m divided by 190 m m equals 11.05 equals 11 r i s e r s

U n i t R i s e L o w e r F of l i g of h of t equals 2100 m m divided by 11 equals 191 m m

The unit run will be the same as for the upper flight.

U n i t R u n L o w e r F of l i g of h of t equals U n i t R u n U p p e r F of l i g of h of t

imageSince we need to now consider the headroom in the R.O., we will use the same formula as for a straight flight of stairs, with two exceptions:

 

– We must subtract the total rise of the upper flight from the headroom and floor construction
– We must add the landing to the R.O. as with the upper flight.

We can place these additions directly into the previous formula:

R period O period L o w e r F of l i g of h of t equals the fraction with numerator H of e a. d r o o m plus F of l o o r C o n s t r u c t i o n minus T o t a. l R i s e U p p e r F of l i g of h of t and denominator U n i t R i s e L o w e r F of l i g of h of t times u n i t r u n plus l a. n d i n g positive 75 m m

R period O period L o w e r F of l i g of h of t equals the fraction with numerator 1950 m m plus 300 m m minus 570 m m and denominator 191 m m times 270 m m plus 1000 m m positive 75 m m

R period O period L o w e r F of l i g of h of t equals 8.7958 times 270 m m plus 1000 m m plus 75 m m equals 3449.9 m m equals 3450 m m

Straight Stairs with a Landing

For a variety of reasons, such as total rise restrictions and aesthetics, a straight run of stairs may come equipped with a landing. If that landing falls within the rough opening, we must take it into account and add it into our calculations. We will use the following as an example:

  • Straight stairs with landing 6 risers up from bottom floor
  • Landing 860 mm x 860 mm
  • Total rise 2805 mm
  • Headroom 1950 mm
  • Upper floor construction 247 mm
  • Unit of rise 187
  • Unit of run 263 mm

Since the unit rise and unit run is given, we will first calculate the R.O. as if there is no landing:

R period O period n o l a. n d i n g equals the fraction with numerator 1950 m m plus 247 m m and denominator 187 m m times 263 m m plus 75 m m equals 11.749 times 263 m m equals 3090 m m

In the above equation, we see that 11.75 uncovered treads are within the stairwell. We can check to see if the landing falls within the stairwell by finding the number of risers and subtracting 6 from this value. If the result is less than 11.75, we know the landing is within the stairwell and must be added.

number sign o f r i s e r s equals 2805 m m division sign 187 equals 15 r i s e r s

R i s e r s a. b o v e l a. n d i n g equals 15 minus 6 equals 9

With a result less than 11.75, we know that the landing is within the stairwell and we must add it to the R.O. that was previously calculated. The landing takes the place of one tread, so we must also subtract one unit run from this value:

R period O period open paren w i t h l a. n d i n g close paren equals 3090 m m plus 860 m m minus 263 m m equals 3687 m m

Review Questions

  1. When laying out a stringer, should the crown be up or down?
  1. Which is the best method of laying out the second stringer to ensure that it matches the first stringer?
a) Repeat the same steps as when laying out the first stringer
b) Set the stringers face to face and transfer the layout marks
c) Cut out the first stringer and use it as a pattern
d) Alternate each step from stringer to stringer in sequence
  1. Explain “dropping the stringer” and the reason for doing so
  2. How much is the stringer dropped if the treads are 38 mm thick?
  3. True or False:
  1. The stringer is always dropped the same amount
  2. When laying out a stair stringer, always start at the top
  1. Calculate the dimensions for the set of stairs given below:
  • Total rise                  2350 mm
  • Proposed rise                  200 mm max.
  • Upper floor construction      273 mm
  • Headroom                  1950 mm
  • Use rule #3                  Rise x Run = 47000
a) Number of risers in the stairs: ___________
b) Unit of rise: _______
c) Number of uncovered treads: _________
d) Unit of run: _________
e) Rough opening length of stairwell: _________
  1. Calculate the dimensions for the set of stairs described below.
  1. Total rise                  2484 mm
  2. Proposed rise                  190 mm
  3. Upper floor construction      270 mm
  4. Headroom required            2050 mm
  5. Use rule #1                  run = 460 mm – rise
a) Number of risers in the stairs: _________
b) Unit of Rise: _________
c) Number of uncovered treads: _________
d) Unit of Run: _________
e) Rough opening length of stairwell: _________
  1. Design a Long L style of stairs and the stairwell using the following dimensions
  • Total Rise                        2720 mm
  • Landing                              2020 above lower floor
  • Proposed unit rise for upper flight      190 max.
  • Use unit of rise for upper as proposed
  • for lower flight
  • Use rule #1                        rise + run = 460
  • Unit of run same both flights
  • Headroom                        1950 mm
  • Upper floor construction            285 mm
  • Size of landing                        1000 mm x 1000 mm
  • Nosing                              25 mm
a) Total rise upper flight is _____________________________________
b) Number of risers in upper flight is _____________________________________
c) Unit of rise in upper flight is _____________________________________
d) Unit of run in upper flight is _____________________________________
e) Total run of upper flight is _____________________________________
f) R.O. length of upper flight is _____________________________________
g) Number of risers in lower flight is _____________________________________
h) Unit of rise in lower flight is _____________________________________
i) Headroom plus floor construction is _____________________________________
j) Number of uncovered treads in lower flight is _____________________________________
k) R.O. length of stairwell for lower flight is _____________________________________
  1. Calculate the stairs for split entries with a fixed landing height

1

2

3

4

Total Rise

2680

2795

2680

2750

Height of landing above lower level

2000

2030

2090

1830

Total rise of upper flight

a)

a)

a)

a)

Number of risers in upper flight

4

4

3

5

To Find unit run, use:

Run = 460 mm – rise

Unit rise of upper flight

b)

b)

b)

b)

Unit run both flights

c)

c)

c)

c)

Number of risers in lower flight

d)

d)

d)

d)

Unit rise is lower flight

e)

e)

e)

e)

Headroom required

1980

2060

2000

1950

Upper floor construction

265

290

345

300

Allowance for finishes in stairwell (upper flight)

75

75

75

75

Allowances for finishes in stairwell (lower flight)

75

75

75

5

Size of landing

1000 x 1000

1000 x 1000

1000 x 1000

1000 x 1000

Rough opening length of upper flight

f)

f)

f)

f)

Headroom + floor construction

g)

g)

g)

g)

Headroom plus floor construction minus rise of upper flight

h)

h)

h)

h)

# Uncovered treads lower

i)

i)

i)

i)

R.O length lower flight

j)

j)

j)

j)

  1. Calculate the contents of the table on the next page using the following dimensions:

Number

Total Rise (mm)

Proposed Rise (mm)

Upper Floor Construction (mm)

Headroom Required (mm)

Allowance for Finishes (mm)

1

2780

200 max.

300

1950

75

2

3125

190 max.

450

2000

75

3

2950

195

330

1950

75

4

2920

180

280

2050

75

5

2870

195 max.

380

2000

75

6

2700

190

260

2050

75

Number

Unit Rise (mm)

Unit Run (mm)

Headroom + U.F.C (mm)

# Uncovered risers

Finished opening (mm)

Rough opening (mm)

1

a)

b)

c)

d)

e)

f)

2

a)

b)

c)

d)

e)

f)

3      

a)

b)

c)

d)

e)

f)

4

a)

b)

c)

d)

e)

f)

5

a)

b)

c)

d)

e)

f)

6

a)

b)

c)

d)

e)

f)

Answers:

  1. Up
  2. C
  3. It is cutting down the first riser at the bottom equal to the thickness of the tread material. This compensates for the gain in height when the treads are applied.
  4. 38 mm
    1. False
    2. False
    1. 12
    2. 195.83 mm
    3. 11.35
    4. 264.17 mm
    5. 3073.33 mm
    1. 13
    2. 191.08 mm
    3. 12.14
    4. 268.92 mm
    5. 3339.69 mm
    1. 700 mm
    2. 4
    3. 175 mm
    4. 285 mm
    5. 855 mm
    6. 1930 mm
    7. 12
    8. 168.33 mm
    9. 2235 mm
    10. 9.12
    11. 3674.2 mm
  1.   1 2 3 4
    Total Rise 2680 2795 2680 2750
    Height of landing above lower level 2000 2030 2090 1830
    Total rise of upper flight a) 680 a) 765 a) 590 a) 920
    Number of risers in upper flight 4 4 3 5
    To Find unit run, use: Run = 460 mm – rise
    Unit rise of upper flight b) 170 b) 191.25 b) 196.67 b) 184
    Unit run both flights c) 290 c) 268.75 c) 263.33 c) 276
    Number of risers in lower flight d) 166.67 d) 184.55 d) 190 d) 183
    Unit rise is lower flight e) 12 e) 11 e) 11 e) 10
    Headroom required 1980 2060 2000 1950
    Upper floor construction 265 290 345 300
    Allowance for finishes in stairwell (upper flight) 75 75 75 75
    Allowances for finishes in stairwell (lower flight) 75 75 75 5
    Size of landing 1000 x 1000 1000 x 1000 1000 x 1000 1000 x 1000
    Rough opening length of upper flight f) 1945 f) 1881.25 f) 1601.67 f) 2179
    Headroom + floor construction g) 2245 g) 2350 g) 2345 g) 2250
    Headroom plus floor construction minus rise of upper flight h) 1565 h) 1585 h) 1755 h) 1330
    # Uncovered treads lower i) 9.39 i) 8.59 i) 9.24 i) 7.27
    R.O length lower flight j) 3798.05 j) 3383.15 j) 3507.34 j) 3080.9
Number Unit Rise (mm) Unit Run (mm) Headroom + U.F.C (mm) # uncovered risers Finished opening (mm) Rough opening (mm)
1 a) 198.57 b) 261.43 c) 2250 d) 11.33 e) 2962.27 f) 3037.27
2 a) 183.82 b) 276.18 c) 2450 d) 13.33 e) 3681 f) 3756
3 a) 196.67 b) 263.33 c) 2280 d) 11.59 e) 3052.79 f) 3127.79
4 a) 182.5 b) 277.5 c) 2330 d) 12.77 e) 3542.88 f) 3617.88
5 a) 191.33 b) 268.67 c) 2380 d) 12.44 e) 3342.05 f) 3417.05
6 a) 192.86 b) 267.14 c) 2310 d) 11.98 e) 3199.7 f) 3274.7

 

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Carpentry Refresher Program Manual Copyright © by Saskatchewan Indian Institute of Technologies-Trades and Industrial is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.